5x^2+96x-576=0

Solution for 5x^2+96x-576=0 equation:

5x^2+96x-576=0

a = 5; b = 96; c = -576;
Δ = b2-4ac
Δ = 962-4·5·(-576)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-144}{2*5}=\frac{-240}{10}
=-24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+144}{2*5}=\frac{48}{10}
=4+4/5
$